Subject: Net Ess

I passed Net Essentials today 08 July 1998 with a score of 862.I'm using the self study course from Wavetech. I also checked any definitions I didn't know using webopedia at http://thetech.pcwebopedia.com and the back  issues of Windows NT magazine at www.winntmag.com and the braindumps.

Everthing I had had been covered in the dumps though I had slightly different wording. Take care and read carefully when this happens as you may go for the wrong answer. Here's an example:

You plan to install a 100Mbps network with 95 users and 1 server which will be housed in the cable room. The building has a suspended ceiling with 1 metre ceiling space. What cabling would you use? Costs should be kept to a minimum.

(choose 1)

(a)coax, (b)fibre-optic,(c)UTP,(d)STP.

Fibre-optic and Cat5 UTP will support 100Mbps however Cat5 UTP wasn't mentioned. (In other questions Cat5 UTP had been specifically referred to). Does the ceiling space have to be used or is this just a red herring? I chose Fibre-optic as it was the only one in the list that would definitely support 100Mbps. It's also the most expensive cable in the list. Make up your own mind.

 Another was the 3 cities only mine had a 16 port RAS server at each location with 8 sending and 8 receiving 28.8Kbps modems at each site.

Required : Be able to connect and transfer data (Yes)

Option 1 To transfer data if a link goes down. (2nd thoughts at home as I can't remember the exact words It may have said Link or it may have said RAS server, READ EVERYTING CAREFULLY).

Option 2 Transfer data with a speed of at least 1Mbps.

My answer was it satisfied the required and one option however if it said RAS server went down only the 2 remaining sites could still transfer data.

The 2nd Option brings us to the old chestnut Bandwidth of summed Modems.

Is it N*28.8Kbps where N is the number of modems or N*28.8Kbps*100/8 .

I have only seen the 2nd formula in braindumps, despite a lot of research I cannot find it in any text book or white paper. Does anyone have a reliable source for this formula?

Dividing by 8 will convert Kilobits in to KiloBYTES but why do that?

If the formula was right the above would have a bandwidth of 2.88Mbps which is almost twice the bandwidth of T1.

 Robert, Thanks for a wonderful site. It's been a great help to me