Hello again: I passed today my TCP/IP #70-059 adaptive on 12/07/98 with score of 662 req. 570. 25 Qst.. This test is not difficult but required close attention specially when you get hit as it happened to me with a lot of routers mapping and trouble shooting subnets and IP addresses. It was annoying to me even though I was prepared for it. Take plenty of time to solve hard problems, like up to 10 min. on three or four of them and don't be afraid to run out of time because you would get a lot of easy questions in the end to make up. That's what happened unwillingly to me, and still, I finished up with 20 min. left on the clock. All question were similar to the previous dumps so no need to repeat it again. All you need to study for tests is Transcenders and Brain Dumps, Transcenders and Brain Dumps, Transcenders and Brain Dumps, Transcenders and Brain Dumps, Nothing Else. I passed four exams so far relying on those two resources, and red only one material book offered with ATEC. So don't cram your head with cram sessions and books and cbt's these are all wasting of time and money and adding confusions and overwhelming from material quantity to your head. Be simple. Another golden advice take the test in the morning period and don't revise any material on that day make a vow to yourself that you won't touch any papers or books go with fresh brain to the test center I think that will help your confidence instead of going with fear. I am totally against the idea of cramming your brain just before the test, It is a sign of failure. Here is a MUST DO, you must know how to construct the subnetting table as in Ravi (27.3.98) in this site. It is the simplest one I went across, It will take you only 4 min. to construct it before the test begin, ( Do it while you are in tutorial mode) and believe me it will save your ass for sure. DO NOT start without it I repeat DO NOT start without it. I think Ravi missed one important column in the beginning which is the BITS columns so you write down like this
Bits Decimal Subnet (already -2)
2 192
2
3 224
6
4 240
14
5 248
30
6 252
62
7 254
126
8 255
254
***Note*** the three other colums(host ID's) results are calculated already
with the subtraction of 1(one)keeping in mind that the Zero's are excluded
(not taken into considerations)
Why it is important? because if you want to divide the subnet for Host ID's to form
the Valid IP address you pick the Bit # corresponding to the mask you want and
calculate the Weight of the first starting high bit from right and then increment the same
weight for each subnet till you reach the Sub Mask you have chosen. for Example. If
you were given and Class B IP address as 130.50.7.1 with Mask of 255.255.248.0 and
you want to determine if this IP is valid or not. Here what you do:
Mask 248 correspond to Bit # 5 or in Binary 11111000 (notice 5 ones) than the weight of
the first one (1) from right is 8 then each subnet ( 30 for this example) will
increment by 8 like: 130.50.8.1//130.50.16.1//130.50.24.1//130.50.32.1//
etc. up to 130.50.247.254 So the given IP above is invalid. You see it is easy and
fast with this table. And also put note on the top of the subnet column that the results
are already subtracted two from it just to eliminate confusions if you were using other
methods and tables. Another example for the same IP and problem above but
different mask as 255.255.252.0 Solution: the bit corresponding to Mask 252 is 6 or
in Binary 11111100 ( notice 6 ones) the weight or incrementing is 4. would look like
130.50.4.1//130.50.8.1//130.50.12.1// etc. up to 130.50.251.254
(62 subnet in this ex.) so the IP is valid.
Here is a XMAS gift for you go to web site www.net3group.com and download for yourself the fantastic IP and Subnetting Calculator it will do the magic job for you.
well I have one more to go IIS 4 and I am sure I 'll beat that sucker...
See you in other section and I thank this site and your generousity
and God bless you all.
Lee Beirut