I just passed TCP/IP4.0. This is one of toughest of all. You should really understand the concepts.

1.What is the utility to purge the contents of the NetBIOS name cache?

 

2. What is the utility to view who are all currently having TCP/IP Connection with your Workstation?

 

3. What is the utility to monitor the Ethernet traffic and the TCP/IP stasticts?

 

4. Which utility will you use to export the statistics collected to a spreadsheet for future analysis?

 

5. Your NT Server in your office is connected via RAS to the Internet ISP Server through the ISDN communication. Now you want the Windows 95 workstation users in your internel subnet to get connected to the ISP. How will you do that?

 

6. You want to send the print jobs to a UNIX workstation from the windows NT Workstations. Which utility will you use? LPR

 

7. You want to view the print jobs that are sent to UNIX printer from a windows based Workstation. Which utility will you use? LPQ

 

8. You are configuring a NT Server a which is going to be used as a Mail Server. What is Host record you will use?

 

9. You want to monitor the NT Workstation performance from a Unix client. How will you do it? What Software (utility?) at NT Workstation and at Unix host?

 

10. Hosts file entry. When you say "ftp product" you get connected to the ftp server. You cannot by "FTP 157.51.25.110" .Why?

 

157.21.36.121 UNIX Product

 

157.51.25.110 Product developer

 

11. How will you log on to a Domain controller which is in another domain and for that what entries do you require at your Workstation's lmhosts file?

 

 

Here is a easy way to create Subnet table:

 

Decimal

Subnet
Hosts in ClassA Hosts in Class B Hosts in Class C

192

2

4,194,302

16,382

62

224

6

2,097,150

8,190

30

240

14

1,048,574

4,094

14

248

30

524,286

2,046

6

252

62

262,142

1,022

2

254

126

131,070

510

N/A

255

254

65,534

254

N/A

 

1 2 3 4 5

 

 

 

To get column 1

 

192 + 32 =224

224 + 16 =240

240 + 8 = 248

248 + 4 = 252

252 + 2 = 254

254 + 1 = 255

 

 

To get column 2 use (n*2) + 2, where n = 2, 6, 14… So…

 

(2*2)+2=6

(6*2)+2=14 and so on….

 

 

To get columns 3, 4 you should start from bottom and remember 65, 534 and 254 then use the same formula (n*2) + 2

 

This may seem to be silly but I used this technique to create the table fast before exam.

 

Subnetting Qs are the easiest one’s…so you should save time answering these quickly. Keep an eye on time…RUNNING FAST.

 

Good luck…

Ravi